Solution of the Week #564 - Comparea

If we assume the square is a unit square, then the triangular region has area 1/2.

The radius of the large circle is sqrt(2)/2

The radius of the smaller circle is 2-sqrt(2).

The area of the crescent region is therefore: (4*sqrt(2)-11/2)*pi, or about 0.493.

Therefore the triangle area is very slightly larger than the crescent area.