Solution of the Week #593 - The Trisected Chord

If we call the radius of the circle r, then using intersecting chords:

8*4 = (r+9)*(r-9)

32 = r^2-81

r^2 = 113

The area of the circle is pi*r^2

113*pi = 354.9999699, 355 to the nearest integer. (355/113 is a famously good approximation for pi).